NCERT · Class 12 · Physics · Electrostatic Potential and CapacitanceThe energy density $u$ (energy per unit volume) in an electric field $E$ in free space is given by:
Step-by-Step Solution
The energy density stored in an electric field in vacuum is given by $u = \frac{1}{2} \varepsilon_0 E^2$.
Detailed Options Breakdown
Option : $\frac{1}{2} \varepsilon_0 E$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrostatic Potential and Capacitance.
Option 1: $\frac{1}{2} \varepsilon_0 E^2$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $\varepsilon_0 E^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrostatic Potential and Capacitance.
Option 3: $\frac{1}{2 \varepsilon_0} E^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrostatic Potential and Capacitance.
💡 Study Guide: This question tests core syllabus concepts from Electrostatic Potential and Capacitance. For formulas, key summaries, and mock exam reference guides, read the full Electrostatic Potential and Capacitance Revision Notes.