MCQChemistry

NCERT · Class 12 · Chemistry · ElectrochemistryWhat is the cell constant of a conductivity cell having distance between electrodes $l$ and cross-sectional area $A$?

Step-by-Step Solution

The correct option is $l/A$. The cell constant ($G^$) is defined as the ratio of the distance between the electrodes ($l$) to the cross-sectional area of the electrodes ($A$). It is expressed as $G^ = l/A$. Its unit is cm⁻¹ or m⁻¹.

Detailed Options Breakdown
Option : $A/l$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrochemistry.

Option 1: $l/A$ (Correct Answer)

Correct choice. Refer to the step-by-step verified solution guidelines above for details.

Option 2: $l \times A$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrochemistry.

Option 3: $A^2/l$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrochemistry.

💡 Study Guide: This question tests core syllabus concepts from Electrochemistry. For formulas, key summaries, and mock exam reference guides, read the full Electrochemistry Revision Notes.
← All Chapter QuestionsChemistry Chapters