NCERT · Class 12 · Chemistry · Chemical KineticsFor a reaction $A \rightarrow B$, the rate of reaction doubles when the concentration of $A$ is increased by 4 times. The order of the reaction is:
Step-by-Step Solution
Let Rate $= k[A]^n$. Given that $2 \times \text{Rate} = k(4[A])^n$. Dividing the equations gives $2 = 4^n$, which implies $(2^1) = (2^2)^n$, so $2n = 1$ or $n = 0.5$ (or $1/2$).
Detailed Options Breakdown
Option : 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Chemical Kinetics.
Option 1: 2
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Chemical Kinetics.
Option 2: 0.5 (or 1/2) (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: 0
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Chemical Kinetics.
💡 Study Guide: This question tests core syllabus concepts from Chemical Kinetics. For formulas, key summaries, and mock exam reference guides, read the full Chemical Kinetics Revision Notes.