NCERT · Class 11 · Physics · System of Particles and Rotational MotionA solid cylinder and a hollow cylinder of same mass and outer radius roll down an inclined plane from the same height without slipping. Which one reaches the bottom first?
Step-by-Step Solution
Acceleration down an inclined plane is $a = \frac{g \sin\theta}{1 + k^2/R^2}$. The solid cylinder has a smaller $k^2/R^2$ ratio ($1/2$) than the hollow cylinder ($1$), so it has a greater acceleration and reaches the bottom first.
Detailed Options Breakdown
Option : Solid cylinder (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: Hollow cylinder
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 2: Both reach at the same time
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 3: Depends on the angle of inclination only
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
💡 Study Guide: This question tests core syllabus concepts from System of Particles and Rotational Motion. For formulas, key summaries, and mock exam reference guides, read the full System of Particles and Rotational Motion Revision Notes.