NCERT · Class 11 · Physics · System of Particles and Rotational MotionFor a rigid body executing pure rolling motion on a stationary flat surface without slipping, the linear velocity of the point of contact with the ground is:
Step-by-Step Solution
In pure rolling without slipping, the forward translational velocity ($v_{cm}$) cancels out the backward tangential velocity ($v = \omega R$) at the contact point, resulting in a net instantaneous velocity of zero.
Detailed Options Breakdown
Option : Zero (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $v_{cm}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 2: $2v_{cm}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 3: $\omega R / 2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
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