NCERT · Class 11 · Physics · Mechanical Properties of SolidsThe elastic potential energy stored per unit volume of a stretched wire is given by:
Step-by-Step Solution
The elastic energy density (energy per unit volume) stored in a stretched wire is given by the formula: $u = \frac{1}{2} \times \text{Stress} \times \text{Strain}$.
Detailed Options Breakdown
Option : $\frac{1}{2} \times \text{Stress} \times \text{Strain}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $\text{Stress} \times \text{Strain}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Solids.
Option 2: $\frac{1}{2} \times \frac{\text{Stress}}{\text{Strain}}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Solids.
Option 3: $\frac{\text{Stress}}{\text{Strain}}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Solids.
💡 Study Guide: This question tests core syllabus concepts from Mechanical Properties of Solids. For formulas, key summaries, and mock exam reference guides, read the full Mechanical Properties of Solids Revision Notes.