NCERT · Class 11 · Physics · Mechanical Properties of FluidsThe excess pressure inside a liquid drop of radius $R$ and surface tension $T$ is:
Step-by-Step Solution
A liquid drop has only one free surface. Therefore, the excess pressure inside a liquid drop is $P_{excess} = \frac{2T}{R}$.
Detailed Options Breakdown
Option : $\frac{2T}{R}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $\frac{4T}{R}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
Option 2: $\frac{T}{R}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
Option 3: $\frac{T}{2R}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
💡 Study Guide: This question tests core syllabus concepts from Mechanical Properties of Fluids. For formulas, key summaries, and mock exam reference guides, read the full Mechanical Properties of Fluids Revision Notes.