NCERT · Class 11 · Mathematics · Trigonometric FunctionsFind the degree measure of the angle subtended at the centre of a circle of radius $100$ cm by an arc of length $22$ cm (use $\pi = \frac{22}{7}$).
We know that $\theta = \frac{l}{r}$. Here, $l = 22$ cm and $r = 100$ cm. So, $\theta = \frac{22}{100}$ radians. Converting this to degrees: $\theta = \frac{22}{100} \times \frac{180}{\pi} = \frac{22}{100} \times \frac{180 \times 7}{22} = \frac{63}{5}^{\circ} = 12\frac{3}{5}^{\circ} = 12^{\circ} \left(\frac{3}{5} \times 60\right)' = 12^{\circ} 36'$.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.
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Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.