NCERT · Class 11 · Chemistry · Redox ReactionsWhat is the oxidation number of Chromium (Cr) in $K2Cr2O7$?
Step-by-Step Solution
Let the oxidation number of Cr be $x$. $2(+1) + 2x + 7(-2) = 0 \implies 2 + 2x - 14 = 0 \implies 2x = 12 \implies x = +6$.
Detailed Options Breakdown
Option : +3
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Redox Reactions.
Option 1: +6 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: +7
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Redox Reactions.
Option 3: +5
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Redox Reactions.
💡 Study Guide: This question tests core syllabus concepts from Redox Reactions. For formulas, key summaries, and mock exam reference guides, read the full Redox Reactions Revision Notes.