NCERT · Class 11 · Chemistry · EquilibriumWhat is the relationship between solubility ($S$) and solubility product ($K{sp}$) for a salt of $MX2$ type?
Step-by-Step Solution
For $MX_2(s) \rightleftharpoons M^{2+} + 2X^-$, $[M^{2+}] = S$ and $[X^-] = 2S$. $K_{sp} = [M^{2+}][X^-]^2 = S \times (2S)^2 = 4S^3$.
Detailed Options Breakdown
Option : $K_{sp} = S^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
Option 1: $K_{sp} = 2S^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
Option 2: $K_{sp} = 4S^3$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: $K_{sp} = 27S^4$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
💡 Study Guide: This question tests core syllabus concepts from Equilibrium. For formulas, key summaries, and mock exam reference guides, read the full Equilibrium Revision Notes.