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NCERT · Class 10 · Science · Metals and Non-metals(a) What is corrosion? Explain the conditions required for the rusting of iron, and describe three effective methods used to prevent corrosion. (b) Numerical Problem: A blast furnace process uses pure Hematite ore ($Fe2O3$) to extract iron metal according to the reaction: $$Fe2O3(s) + 3CO(g) \rightarrow 2Fe(s) + 3CO2(g)$$\nCalculate the maximum theoretical mass of pure iron (in grams) that can be extracted from $800\text{ g}$ of pure Hematite ($Fe2O3$). (Given atomic masses: $Fe = 56\text{ u}$, $O = 16\text{ u}$)

Step-by-Step Solution

Part (a): Corrosion and Prevention

Corrosion:\nCorrosion is the process in which metals are gradually eaten away by the action of air, moisture, or chemicals (like acids) on their surface.

  • Example: Rusting of iron, tarnishing of silver (formation of $Ag_2S$), and formation of a green coating on copper ($CuCO_3\cdot Cu(OH)_2$).

Conditions Required for Rusting of Iron:

  1. Presence of Air (Oxygen): Oxygen is necessary for oxidation of iron.
  2. Presence of Water/Moisture: Water vapor acts as a medium for the chemical reaction to form hydrated iron oxides ($Fe_2O_3\cdot xH_2O$).

Methods to Prevent Corrosion:

  1. Galvanization: Coating iron articles with a thin layer of zinc metal. Zinc protects iron because it is more reactive and oxidizes preferentially.
  2. Alloying: Mixing iron with other metals/non-metals to alter its properties (e.g., Stainless steel, made by mixing iron with chromium and nickel, does not rust).
  3. Painting, Greasing, or Oiling: Applying a protective coat on the metal surface prevents direct contact with air and moisture.

Part (b): Numerical Solution

1. Calculate Molar Mass of $Fe_2O_3$:

  • Atomic mass of $Fe = 56\text{ u}$
  • Atomic mass of $O = 16\text{ u}$ $$\text{Molar mass of } Fe_2O_3 = (2 \times 56) + (3 \times 16) = 112 + 48 = 160\text{ g/mol}$$

2. Calculate Molar Mass of Iron ($2Fe$) produced: $$\text{Mass of } 2Fe = 2 \times 56 = 112\text{ g/mol}$$

3. Stoichiometric Relationship:\nFrom the chemical reaction: $$160\text{ g of } Fe_2O_3 \text{ yields } 112\text{ g of } Fe$$

4. Mass of Iron obtained from $800\text{ g}$ of $Fe_2O_3$: $$\text{Mass of } Fe = \left( \frac{112\text{ g}}{160\text{ g}} \right) \times 800\text{ g}$$ $$\text{Mass of } Fe = 0.7 \times 800\text{ g} = 560\text{ g}$$

Final Answer:\nThe maximum theoretical mass of pure iron extracted is $560\text{ g}$.

💡 Study Guide: This question tests core syllabus concepts from Metals and Non-metals. For formulas, key summaries, and mock exam reference guides, read the full Metals and Non-metals Revision Notes.
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