NCERT · Class 10 · Science · Chemical Reactions and EquationsA 3.0 g sample of calcium carbonate (CaCO3) is heated in a crucible. Write a balanced chemical equation for the reaction and calculate the mass of calcium oxide (CaO) produced.

Calcium Carbonate Decomposition Reaction:

CaCO3 → CaO + CO2

Step 1: Calculate the number of moles of CaCO3:

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 = 3.0 g

Number of moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3

= 3.0 g / 100 g/mol

= 0.03 mol

Step 2: Calculate the number of moles of CaO produced:

From the balanced equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO.

Number of moles of CaO produced = number of moles of CaCO3

= 0.03 mol

Step 3: Calculate the mass of CaO produced:

Molar mass of CaO = 56 g/mol

Mass of CaO produced = number of moles of CaO produced × molar mass of CaO

= 0.03 mol × 56 g/mol

= 1.68 g

Conclusion:

The mass of calcium oxide (CaO) produced is 1.68 g.