NCERT · Class 10 · Science · Acids, Bases and SaltsCalculate the molarity of a solution containing 25 grams of sodium chloride (NaCl) dissolved in 250 milliliters of water.
Step-by-Step Solution
To calculate the molarity of the solution, we need to know the number of moles of sodium chloride (NaCl) dissolved in the solution.
The molar mass of NaCl is 58.44 g/mol. To find the number of moles, we can use the formula:
moles = mass/molar mass
Plugging in the values, we get:
moles = 25 g / 58.44 g/mol = 0.428 mol
Next, we need to find the volume of the solution in liters. Since the volume is given in milliliters, we can convert it to liters by dividing by 1000:
volume = 250 mL / 1000 = 0.25 L
Now, we can use the formula for molarity:
molarity = moles/volume
Plugging in the values, we get:
molarity = 0.428 mol / 0.25 L = 1.71 M
Therefore, the molarity of the solution is 1.71 M.
💡 Study Guide: This question tests core syllabus concepts from Acids, Bases and Salts. For formulas, key summaries, and mock exam reference guides, read the full Acids, Bases and Salts Revision Notes.