NCERT · Class 10 · Mathematics · Areas Related to CirclesThe area of a quadrant of a circle whose circumference is 22 cm is:
Given circumference $2\pi r = 22$, so $r = \frac{22}{2\pi} = \frac{11}{\pi}$. Area of the quadrant = $\frac{1}{4} \pi r^2 = \frac{1}{4} \times \pi \times \left(\frac{11}{\pi}\right)^2 = \frac{1}{4} \times \frac{121}{\pi} = \frac{121}{4 \times \frac{22}{7}} = \frac{121 \times 7}{4 \times 22} = \frac{77}{8}\text{ cm}^2 = 9.625\text{ cm}^2$.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Areas Related to Circles.
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Incorrect choice. This distractor represents a common misunderstanding of the core principles of Areas Related to Circles.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Areas Related to Circles.