Pair of Linear Equations in Two Variables

If a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ has a unique solution, then which of the following conditions is correct?

If the pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ represents coincident lines, then:

The pair of equations $x + y = 14$ and $x - y = 4$ has the solution:

Graphical representation of the equations $x = a$ and $y = b$ represents two lines which are:

For what value of $k$ will the equations $3x - y - 5 = 0$ and $6x - 2y - k = 0$ have no solution?

The degree of a linear equation in two variables is:

The pair of equations $y = 0$ and $y = -7$ has:

If the system of equations $2x + 3y = 7$ and $2ax + (a + b)y = 28$ has infinitely many solutions, then:

If $2x + 3y = 11$ and $2x - 4y = -24$, then the value of $m$ in $y = mx + 3$ is:

If $2x + y = 7$ and $x + 2y = 8$, then the value of $x + y$ is:

If a pair of linear equations is consistent, then the lines represented by them are:

The point of intersection of the line $3x + 2y = 12$ with the x-axis is:

For what value of $k$ will the pair of equations $kx + 2y = 5$ and $3x + y = 1$ have a unique solution?

The sum of two numbers is 35 and their difference is 13. The numbers are:

The pair of equations $x + 2y + 5 = 0$ and $-3x - 6y + 1 = 0$ has:

In equation $2x + 3y = 13$, if $x = 2$, then the value of $y$ is:

If $x = a, y = b$ is the solution of the equations $x - y = 2$ and $x + y = 4$, then the values of $a$ and $b$ are respectively:

For what value of $c$ does the pair of equations $cx - y = 2$ and $6x - 2y = 3$ have no solution?

The number of solutions of the pair of linear equations $2x + 3y = 5$ and $4x + 6y = 15$ is:

If a pair of linear equations is inconsistent, then the graph of these equations will be:

For what value of $k$ does the pair of linear equations $x + 2y - 3 = 0$ and $5x + ky + 7 = 0$ represent parallel lines?

What is the solution of the pair of linear equations $x + y = 14$ and $x - y = 4$?

For what value of $k$ will the following pair of linear equations have infinitely many solutions? $$kx + 3y = k - 3$$ $$12x + ky = k$$