MP Board · Class 9 · Science · MotionA stone is thrown vertically upwards with an initial velocity of $5\text{ m/s}$. If the acceleration due to gravity is $10\text{ m/s}^2$ downward, what is the maximum height reached by the stone?
Step-by-Step Solution
Given: $u = 5\text{ m/s}$, $v = 0\text{ m/s}$ (at maximum height), $a = -10\text{ m/s}^2$.\nUsing $v^2 - u^2 = 2as$: $$0 - (5)^2 = 2(-10)s$$ $$-25 = -20s \implies s = \frac{25}{20} = 1.25\text{ m}$$
Detailed Options Breakdown
Option : $1.25\text{ m}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $2.5\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Motion.
Option 2: $5\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Motion.
Option 3: $0.5\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Motion.
💡 Study Guide: This question tests core syllabus concepts from Motion. For formulas, key summaries, and mock exam reference guides, read the full Motion Revision Notes.