MP Board · Class 9 · Science · Improvement in Food ResourcesA farmer owns a rectangular agricultural land measuring 250 metres in length and 200 metres in width. For cultivating a high-yielding cereal crop, the recommended application rate of Urea fertilizer is 120 kg per hectare ($1\text{ hectare} = 10,000\text{ m}^2$). \nCalculate: (a) The total area of the field in hectares. (b) The total mass of Urea fertilizer required for the entire agricultural field.

Solution:

Given:

• Length of field ($l$) = $250\text{ m}$
• Width of field ($b$) = $200\text{ m}$
• Recommended Urea application rate = $120\text{ kg/hectare}$
• Conversion factor: $1\text{ hectare} = 10,000\text{ m}^2$

(a) Calculation of Area in Hectares:

• Area of rectangular field ($A$) = $\text{Length} \times \text{Width}$ $$A = 250\text{ m} \times 200\text{ m} = 50,000\text{ m}^2$$

• Converting area to hectares: $$\text{Area in hectares} = \frac{50,000\text{ m}^2}{10,000\text{ m}^2/\text{hectare}} = 5\text{ hectares}$$

(b) Calculation of Total Urea Required:

• Total Urea required = $\text{Area in hectares} \times \text{Urea rate per hectare}$ $$\text{Total Urea} = 5\text{ hectares} \times 120\text{ kg/hectare} = 600\text{ kg}$$

Final Answer:

• (a) The area of the field is 5 hectares.
• (b) The total Urea fertilizer required is 600 kg.