MP Board · Class 8 · Mathematics · Comparing QuantitiesFind the compound interest on ₹10,000 for 2 years at 10% per annum compounded annually.
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Step-by-Step Solution
A = P(1 + R/100)^n = 10000 × (1 + 10/100)^2 = 10000 × (11/10)^2 = ₹12,100.\nCompound Interest (CI) = A - P = 12,100 - 10,000 = ₹2,100.
Detailed Options Breakdown
Option : ₹2,000
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Comparing Quantities.
Option 1: ₹2,100 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: ₹1,200
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Comparing Quantities.
Option 3: ₹2,200
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Comparing Quantities.
💡 Study Guide: This question tests core syllabus concepts from Comparing Quantities. For formulas, key summaries, and mock exam reference guides, read the full Comparing Quantities Revision Notes.