MP Board · Class 12 · Physics · Wave OpticsWhat is the phase difference corresponding to a path difference of lambda?
Step-by-Step Solution
The correct answer is 2 * pi. The relation between phase difference (phi) and path difference (Delta x) is given by phi = (2 * pi / lambda) * Delta x. Substituting Delta x = lambda gives phi = 2 * pi radians.
Detailed Options Breakdown
Option : pi / 2
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Wave Optics.
Option 1: pi
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Wave Optics.
Option 2: 2 * pi (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: pi / 4
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Wave Optics.
💡 Study Guide: This question tests core syllabus concepts from Wave Optics. For formulas, key summaries, and mock exam reference guides, read the full Wave Optics Revision Notes.