MP Board · Class 12 · Physics · Electric Charges and FieldsWhat is the electric field intensity inside a uniformly charged thin spherical shell? Explain the reason using Gauss's law.

The electric field intensity inside a uniformly charged thin spherical shell is zero at all interior points. According to Gauss's law, $\oint \vec{E} \cdot d\vec{A} = \frac{q_{\text{enclosed}}}{\varepsilon_0}$. Since all charge resides entirely on the outer surface of the shell, the enclosed charge $q_{\text{enclosed}}$ inside any Gaussian surface drawn inside the shell is zero ($q = 0$), resulting in $E = 0$.