MP Board · Class 12 · Physics · Electric Charges and FieldsIf the distance between two point charges is doubled, the electrostatic force between them becomes:
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Step-by-Step Solution
According to Coulomb's law, $F \propto \frac{1}{r^2}$. If distance is doubled ($r' = 2r$), the new force becomes $F' = \frac{F}{2^2} = \frac{F}{4}$ (one-fourth).
Detailed Options Breakdown
Option : One-fourth (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: Double
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Option 2: Four times
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Option 3: Half
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
💡 Study Guide: This question tests core syllabus concepts from Electric Charges and Fields. For formulas, key summaries, and mock exam reference guides, read the full Electric Charges and Fields Revision Notes.