MP Board · Class 12 · Physics · Dual Nature of Radiation and MatterThe slope of the graph between stopping potential ($V0$) and frequency ($\nu$) in photoelectric emission gives:
Step-by-Step Solution
The Einstein's photoelectric equation is $eV_0 = h\nu - \phi_0$, which can be rewritten as $V_0 = \left(\frac{h}{e}\right)\nu - \frac{\phi_0}{e}$. Comparing this with the equation of a straight line $y = mx + c$, the slope $m$ is equal to $\frac{h}{e}$.
Detailed Options Breakdown
Option : $h$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.
Option 1: $\frac{h}{e}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $e$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.
Option 3: $\frac{e}{h}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.
💡 Study Guide: This question tests core syllabus concepts from Dual Nature of Radiation and Matter. For formulas, key summaries, and mock exam reference guides, read the full Dual Nature of Radiation and Matter Revision Notes.