MP Board · Class 12 · Biology · Human ReproductionA couple is undergoing fertility treatments. Analysis of the male partner's semen reveals a total sperm count of $2.4 \times 10^8$ spermatozoa in a standard ejaculate volume of 4.0 mL. Furthermore, microscopic examination shows that 60% of these spermatozoa have normal overall shape and size (morphology), and of these, 50% show vigorous forward motility. Based on standard WHO fertility guidelines which require a minimum of 40% normal morphology and 32% progressive motility for normal fertility, calculate: The sperm concentration per mL of semen. The total number of spermatozoa exhibiting normal morphology. The total number of spermatozoa exhibiting both normal morphology and active progressive motility. Determine if the male partner's sample meets the WHO criteria for normal fertility parameters based on these calculations.
To evaluate the semen sample based on the given parameters, we perform the step-by-step calculations as follows:
Given Data:
- Total volume of ejaculate = $4.0\text{ mL}$
- Total sperm count in ejaculate = $2.4 \times 10^8\text{ spermatozoa}$
- Percentage of spermatozoa with normal morphology = $60%$
- Percentage of morphologically normal spermatozoa showing vigorous progressive motility = $50%$
Step 1: Calculate the sperm concentration per mL of semen $$\text{Sperm Concentration} = \frac{\text{Total Sperm Count}}{\text{Total Volume}}$$ $$\text{Sperm Concentration} = \frac{2.4 \times 10^8\text{ spermatozoa}}{4.0\text{ mL}} = 0.6 \times 10^8\text{ spermatozoa/mL} = 6.0 \times 10^7\text{ spermatozoa/mL}$$
Step 2: Calculate the total number of spermatozoa exhibiting normal morphology $$\text{Normal Morphology Count} = \text{Total Sperm Count} \times \left(\frac{\text{Normal Morphology Percentage}}{100}\right)$$ $$\text{Normal Morphology Count} = 2.4 \times 10^8 \times \frac{60}{100} = 2.4 \times 10^8 \times 0.6 = 1.44 \times 10^8\text{ spermatozoa}$$
Step 3: Calculate the total number of spermatozoa exhibiting both normal morphology and active progressive motility $$\text{Motile Normal Sperm Count} = \text{Normal Morphology Count} \times \left(\frac{\text{Motility Percentage}}{100}\right)$$ $$\text{Motile Normal Sperm Count} = 1.44 \times 10^8 \times \frac{50}{100} = 1.44 \times 10^8 \times 0.5 = 0.72 \times 10^8\text{ spermatozoa} = 7.2 \times 10^7\text{ spermatozoa}$$
Step 4: Determine compliance with WHO criteria
- Morphology Criterion: The sample has $60%$ normal morphology, which is well above the WHO minimum threshold of $40%$.
- Motility Criterion: The percentage of progressively motile sperm among normal ones is $50%$ of the normal fraction (or overall, $50%$ of $60% = 30%$ of total motile normal, but let's check progressive motility of total: $0.72 \times 10^8 / 2.4 \times 10^8 = 30%$ total progressive). Wait, let's check standard WHO progressive motility threshold: minimum $32%$ total progressive motility. Here, total progressive motility of the sample is $30%$, which is slightly below the WHO reference value of $32%$. Therefore, while concentration and morphology are satisfactory, the progressive motility requires clinical review.