MP Board · Class 11 · Physics · WavesThe phase difference $\Delta \phi$ corresponding to a path difference $\Delta x$ in a wave is given by:
Step-by-Step Solution
Correct Option: $\Delta \phi = \frac{2\pi}{\lambda} \Delta x$ \nThe relation between phase difference $\Delta \phi$ and path difference $\Delta x$ is $\Delta \phi = \frac{2\pi}{\lambda} \Delta x$, where $\lambda$ is the wavelength.
Detailed Options Breakdown
Option : $\Delta \phi = \frac{\lambda}{2\pi} \Delta x$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Waves.
Option 1: $\Delta \phi = \frac{2\pi}{\lambda} \Delta x$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $\Delta \phi = \frac{\pi}{\lambda} \Delta x$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Waves.
Option 3: $\Delta \phi = 2\pi \lambda \Delta x$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Waves.
💡 Study Guide: This question tests core syllabus concepts from Waves. For formulas, key summaries, and mock exam reference guides, read the full Waves Revision Notes.