MP Board · Class 11 · Physics · OscillationsA body of mass $1\text{ kg}$ is attached to a spring of spring constant $100\text{ N/m}$. The time period of its oscillation is:
Step-by-Step Solution
Time period of a spring-mass system is $T = 2\pi \sqrt{\frac{m}{k}} = 2\pi \sqrt{\frac{1}{100}} = \frac{2\pi}{10} = 0.2\pi\text{ s}$.
Detailed Options Breakdown
Option : $0.2\pi\text{ s}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $2\pi\text{ s}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 2: $0.1\pi\text{ s}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 3: $\pi\text{ s}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.