MP Board · Class 11 · Physics · OscillationsIf a simple pendulum is taken to Moon where acceleration due to gravity is $g/6$, its time period will increase by a factor of:
Step-by-Step Solution
Time period $T = 2\pi \sqrt{\frac{L}{g}}$. On Moon, $g' = \frac{g}{6}$, so $T' = 2\pi \sqrt{\frac{L}{g/6}} = \sqrt{6} T$. The time period increases by a factor of $\sqrt{6}$.
Detailed Options Breakdown
Option : $\sqrt{6}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 6
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 2: 36
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 3: $\frac{1}{\sqrt{6}}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.