MP Board · Class 11 · Physics · OscillationsWhat is the approximate length of a second's pendulum on Earth?
Step-by-Step Solution
A second's pendulum has a time period $T = 2\text{ s}$. Using $T = 2\pi \sqrt{\frac{L}{g}} \Rightarrow 2 = 2\pi \sqrt{\frac{L}{9.8}} \Rightarrow L = \frac{9.8}{\pi^2} \approx 0.993\text{ m} \approx 1\text{ m}$.
Detailed Options Breakdown
Option : $0.5\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 1: $1\text{ m}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $2\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 3: $0.25\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.