MP Board · Class 11 · Physics · OscillationsAt the mean position ($x = 0$), a body executing SHM has:
Step-by-Step Solution
At $x = 0$, displacement is zero, so potential energy $\text{PE} = \frac{1}{2} k x^2 = 0$. The velocity is maximum, so kinetic energy is maximum.
Detailed Options Breakdown
Option : Maximum potential energy and zero kinetic energy
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 1: Maximum kinetic energy and zero potential energy (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: Both kinetic and potential energy zero
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 3: Maximum kinetic and maximum potential energy
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.