MP Board · Class 11 · Physics · Motion in a Straight LineIf the position of an object is given by x = a + bt^2, where a and b are constants, then its instantaneous acceleration at time t is:
📊Student Analytics & Stats
Total Attempts: 4
Accuracy Rate: 25%
Step-by-Step Solution
Velocity v = dx/dt = 2bt. Acceleration a = dv/dt = 2b. Thus, the acceleration is constant and equal to 2b. Therefore, the correct option is 2b.
Detailed Options Breakdown
Option : 2bt
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Motion in a Straight Line.
Option 1: 2b (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: b
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Motion in a Straight Line.
Option 3: a + 2bt
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Motion in a Straight Line.
💡 Study Guide: This question tests core syllabus concepts from Motion in a Straight Line. For formulas, key summaries, and mock exam reference guides, read the full Motion in a Straight Line Revision Notes.