MP Board · Class 11 · Physics · Mechanical Properties of FluidsAccording to Stokes' law, the terminal velocity ($vt$) of a small spherical body falling in a viscous medium is directly proportional to:
Step-by-Step Solution
According to Stokes' law formula $v_t = \frac{2}{9}\frac{r^2(\rho - \sigma)g}{\eta}$, the terminal velocity is directly proportional to the square of the radius ($r^2$) of the spherical body.
Detailed Options Breakdown
Option : Radius ($r$)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
Option 1: Square of the radius ($r^2$) (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: Cube of the radius ($r^3$)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
Option 3: Inverse of radius ($1/r$)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Fluids.
💡 Study Guide: This question tests core syllabus concepts from Mechanical Properties of Fluids. For formulas, key summaries, and mock exam reference guides, read the full Mechanical Properties of Fluids Revision Notes.