MP Board · Class 11 · Physics · Laws of MotionA bullet of mass 0.04 kg is fired from a gun of mass 20 kg. If the speed of the bullet is 300 m/s, the recoil speed of the gun is:
Step-by-Step Solution
Using conservation of linear momentum: $m_1 v_1 + m_2 v_2 = 0$. Given $m_1 = 0.04\text{ kg}$, $v_1 = 300\text{ m/s}$, $m_2 = 20\text{ kg}$. $v_2 = - \frac{0.04 \times 300}{20} = -0.6\text{ m/s}$. The magnitude is 0.6 m/s.
Detailed Options Breakdown
Option : 0.6 m/s (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 1.2 m/s
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Laws of Motion.
Option 2: 0.3 m/s
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Laws of Motion.
Option 3: 6.0 m/s
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Laws of Motion.
💡 Study Guide: This question tests core syllabus concepts from Laws of Motion. For formulas, key summaries, and mock exam reference guides, read the full Laws of Motion Revision Notes.