MP Board · Class 11 · Physics · GravitationThe relation between escape velocity ($ve$) and orbital velocity ($vo$) for a satellite near the surface of Earth is:
Step-by-Step Solution
Escape velocity is $v_e = \sqrt{\frac{2GM}{R}}$ and orbital velocity is $v_o = \sqrt{\frac{GM}{R}}$. Thus, $v_e = \sqrt{2} v_o$.
Detailed Options Breakdown
Option : $v_e = v_o$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 1: $v_e = \sqrt{2} v_o$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $v_o = \sqrt{2} v_e$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 3: $v_e = 2 v_o$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.