MCQChemistry

MP Board · Class 11 · Chemistry · Structure of AtomHeisenberg's uncertainty principle is mathematically represented as:

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Total Attempts: 5
Accuracy Rate: 60%
Step-by-Step Solution

Heisenberg's uncertainty principle states that $\Delta x \cdot \Delta p \ge \frac{h}{4\pi}$, where $\Delta x$ is position uncertainty and $\Delta p$ is momentum uncertainty.

Detailed Options Breakdown
Option : $\Delta x \cdot \Delta p \ge \frac{h}{4\pi}$ (Correct Answer)

Correct choice. Refer to the step-by-step verified solution guidelines above for details.

Option 1: $\Delta x \cdot \Delta p \le \frac{h}{4\pi}$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Structure of Atom.

Option 2: $\Delta x \cdot \Delta v \ge \frac{h}{2\pi}$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Structure of Atom.

Option 3: $\Delta x \cdot \Delta p = h$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Structure of Atom.

💡 Study Guide: This question tests core syllabus concepts from Structure of Atom. For formulas, key summaries, and mock exam reference guides, read the full Structure of Atom Revision Notes.
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