Some Basic Concepts of Chemistry
ЁЯУР Formula & Cheat Sheet (English)
MP Board Class 11 Chemistry Quick Revision Notes
Chapter 1: Some Basic Concepts of Chemistry (рд░рд╕рд╛рдпрди рд╡рд┐рдЬреНрдЮрд╛рди рдХреА рдХреБрдЫ рдореВрд▓ рдЕрд╡рдзрд╛рд░рдгрд╛рдПрдБ)
1. Classification of Matter (рджреНрд░рд╡реНрдп рдХрд╛ рд╡рд░реНрдЧреАрдХрд░рдг)
- Matter (рджреНрд░рд╡реНрдп): Anything that has mass and occupies space.
- Pure Substances (рд╢реБрджреНрдз рдкрджрд╛рд░реНрде): Fixed composition.
- Elements (рддрддреНрд╡): Cannot be decomposed into simpler substances (e.g., Na, C, OтВВ).
- Compounds (рдпреМрдЧрд┐рдХ): Formed by two or more elements in a fixed mass ratio (e.g., HтВВO, COтВВ).
- Mixtures (рдорд┐рд╢реНрд░рдг): Variable composition.
- Homogeneous (рд╕рдорд╛рдВрдЧреА): Uniform composition throughout (e.g., Salt solution, Air).
- Heterogeneous (рд╡рд┐рд╖рдорд╛рдВрдЧреА): Non-uniform composition (e.g., Mixture of sand and water).
2. Laws of Chemical Combinations (рд░рд╛рд╕рд╛рдпрдирд┐рдХ рд╕рдВрдпреЛрдЬрди рдХреЗ рдирд┐рдпрдо)
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Law of Conservation of Mass (рджреНрд░рд╡реНрдпрдорд╛рди рд╕рдВрд░рдХреНрд╖рдг рдХрд╛ рдирд┐рдпрдо):
- Given by: Antoine Lavoisier (1789)
- Statement: Matter can neither be created nor destroyed in a chemical reaction.
Total Mass of Reactants = Total Mass of Products
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Law of Definite Proportions (рд╕реНрдерд┐рд░ рдЕрдиреБрдкрд╛рдд рдХрд╛ рдирд┐рдпрдо):
- Given by: Joseph Proust (1799)
- Statement: A chemical compound always contains exactly the same proportion of elements by weight, regardless of its source.
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Law of Multiple Proportions (рдЧреБрдгрд╛рддреНрдордХ рдЕрдиреБрдкрд╛рдд рдХрд╛ рдирд┐рдпрдо):
- Given by: John Dalton (1803)
- Statement: When two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in a ratio of small whole numbers (e.g., CO and COтВВ).
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Gay LussacтАЩs Law of Gaseous Volumes (рдЧреЗ-рд▓реБрд╕рд╛рдХ рдХрд╛ рдЧреИрд╕реАрдп рдЖрдпрддрди рдХрд╛ рдирд┐рдпрдо):
- Statement: When gases react, they do so in volumes which bear a simple whole-number ratio to one another and to the volume of products (if gaseous), at the same temperature and pressure.
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AvogadroтАЩs Law (рдЖрд╡реЛрдЧрд╛рджреНрд░реЛ рдХрд╛ рдирд┐рдпрдо):
- Statement: Equal volumes of all gases under the same conditions of temperature and pressure contain an equal number of molecules.
V тИЭ n(at constant T and P)
3. Atomic Mass, Molecular Mass & Equivalent Mass
- Atomic Mass Unit (amu or u): $1\text{ amu} = \frac{1}{12} \text{th mass of one C-12 atom} = 1.66056 \times 10^{-24} \text{ g}$.
- Average Atomic Mass: $$\text{Average Atomic Mass} = \frac{\sum (\text{Isotopic Mass} \times \text{% Abundance})}{100}$$
- Molecular Mass: Sum of atomic masses of all atoms present in a molecule.
- Equivalent Mass (рддреБрд▓реНрдпрд╛рдВрдХреА рднрд╛рд░):
$$\text{Equivalent Mass (E)} = \frac{\text{Molar Mass}}{\text{Valency factor / n-factor}}$$
- For Acids: $\text{n-factor} = \text{Basicity (number of replaceable } \text{H}^+ \text{ ions)}$
- For Bases: $\text{n-factor} = \text{Acidity (number of replaceable } \text{OH}^- \text{ ions)}$
- For Salts: $\text{n-factor} = \text{Total positive charge on cations}$
4. Mole Concept (рдореЛрд▓ рдЕрд╡рдзрд╛рд░рдгрд╛)
- 1 Mole: Amount of substance containing $6.022 \times 10^{23}$ elementary particles (Avogadro's Number, $N_A$).
Key Mole Formulas:
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In terms of Mass: $$\text{Number of moles } (n) = \frac{\text{Given Mass in grams } (w)}{\text{Molar Mass } (M)}$$
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In terms of Particles: $$\text{Number of moles } (n) = \frac{\text{Given number of particles } (N)}{\text{Avogadro's Number } (N_A)}$$
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In terms of Gas Volume at STP ($0^\circ\text{C}$, $1\text{ atm}$): $$\text{Number of moles } (n) = \frac{\text{Volume of gas in Liters at STP}}{22.4 \text{ L}}$$
5. Percentage Composition & Chemical Formulas
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Mass Percentage of an Element: $$\text{Mass %} = \frac{\text{Mass of element in 1 mole of compound}}{\text{Molar Mass of compound}} \times 100$$
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Empirical Formula (рдореВрд▓рд╛рдиреБрдкрд╛рддреА рд╕реВрддреНрд░): Simplest whole-number ratio of atoms of each element present in a compound.
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Molecular Formula (рдЖрдгреНрд╡рд┐рдХ рд╕реВрддреНрд░): Shows the actual number of atoms of each element present in a molecule of a compound.
Relation between Empirical & Molecular Formula:
$$\text{Molecular Formula} = n \times (\text{Empirical Formula})$$ $$\text{Where, } n = \frac{\text{Molecular Mass}}{\text{Empirical Formula Mass}}$$
6. Stoichiometry & Concentration Terms
Limiting Reagent (рд╕реАрдорд┐рдд рдЕрднрд┐рдХрд░реНрдордХ):
- The reactant that gets completely consumed first in a chemical reaction and limits the amount of product formed.
Concentration Terms for Solutions (рд╡рд┐рд▓рдпрди рдХреА рд╕рд╛рдВрджреНрд░рддрд╛):
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Mass Percentage (% w/w): $$% \text{ (w/w)} = \frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100$$
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Mole Fraction ($x$) (рдореЛрд▓ рдкреНрд░рднрд╛рдЬ):
- For a binary solution of solute $B$ and solvent $A$: $$x_B = \frac{n_B}{n_A + n_B}, \quad x_A = \frac{n_A}{n_A + n_B}$$
- Note: $x_A + x_B = 1$ (Dimensionless quantity)
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Molarity ($M$) (рдореЛрд▓рд░рддрд╛):
- Number of moles of solute dissolved per liter of solution.
- Unit: $\text{mol/L}$ or $\text{M}$ $$\text{Molarity } (M) = \frac{\text{Moles of solute }(n_B)}{\text{Volume of solution in Liters }(V)}$$ $$\text{Formula: } M = \frac{w_B \times 1000}{M_B \times V \text{ (in mL)}}$$
- Temperature dependence: Temperature dependent (changes with $T$ because volume changes).
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Molality ($m$) (рдореЛрд▓рд▓рддрд╛):
- Number of moles of solute present per kilogram ($1000\text{ g}$) of solvent.
- Unit: $\text{mol/kg}$ or $\text{m}$ $$\text{Molality } (m) = \frac{\text{Moles of solute }(n_B)}{\text{Mass of solvent in kg }(W_A)}$$ $$\text{Formula: } m = \frac{w_B \times 1000}{M_B \times w_A \text{ (in grams)}}$$
- Temperature dependence: Independent of temperature (mass does not change with temperature).
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Normality ($N$) (рдиреЙрд░реНрдорд▓рддрд╛):
- Number of gram equivalents of solute per liter of solution. $$\text{Normality } (N) = \frac{w_B \times 1000}{E_B \times V \text{ (in mL)}}$$
- Relation between Normality and Molarity: $$\text{Normality } (N) = \text{Molarity } (M) \times \text{n-factor}$$
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Dilution Formula (рддрдиреБрддрд╛ рд╕рдореАрдХрд░рдг): $$M_1 V_1 = M_2 V_2 \quad \text{and} \quad N_1 V_1 = N_2 V_2$$
7. Significant Figures & Rules (рд╕рд╛рд░реНрдердХ рдЕрдВрдХ)
- All non-zero digits are significant (e.g., $162 \text{ g} \rightarrow 3$ sig. figures).
- Zeros preceding the first non-zero digit are not significant (e.g., $0.0025 \rightarrow 2$ sig. figures).
- Zeros between two non-zero digits are significant (e.g., $2.005 \rightarrow 4$ sig. figures).
- Terminal zeros to the right of the decimal point are significant (e.g., $0.200 \rightarrow 3$ sig. figures).
- Exact numbers (e.g., 2 balls, 20 eggs) have infinite significant figures.
ЁЯТб MP Board High-Yield Quick Revision Tips
- frequently asked differentiate question: Molarity vs Molality
- Molarity depends on volume and changes with temperature.
- Molality depends on mass of solvent and is temperature-independent.
- Standard Value Reminder: Standard molar volume of any ideal gas at STP ($0^\circ\text{C}, 1\text{ atm}$) = $22.4 \text{ Liters}$.
- Always Check Units: Ensure mass is in grams when using $1000$ in Molarity/Molality short formulas!