MP Board · Class 11 · Chemistry · EquilibriumWhat is the value of ionic product of water ($Kw$) at $298 \text{ K}$?
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Total Attempts: 1
Accuracy Rate: 100%
Step-by-Step Solution
At $298 \text{ K}$, the concentration of $[H^+] = 10^{-7} \text{ M}$ and $[OH^-] = 10^{-7} \text{ M}$, making $K_w = [H^+][OH^-] = 10^{-14} \text{ mol}^2\text{L}^{-2}$.
Detailed Options Breakdown
Option : $1 \times 10^{-7}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
Option 1: $1 \times 10^{-14}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $1 \times 10^{-10}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
Option 3: $1 \times 10^{-12}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Equilibrium.
💡 Study Guide: This question tests core syllabus concepts from Equilibrium. For formulas, key summaries, and mock exam reference guides, read the full Equilibrium Revision Notes.