MP Board · Class 10 · Science · Heredity and EvolutionIn a genetic cross between a pure-breeding tall pea plant (TT) and a pure-breeding dwarf pea plant (tt), work out the phenotypic and genotypic ratios for the F1 and F2 generations. Also state the law derived from this monohybrid cross.
Step-by-Step Solution
To determine the phenotypic and genotypic ratios of the monohybrid cross between a pure tall pea plant (TT) and a pure dwarf pea plant (tt), we can follow the step-by-step procedure below:
Step 1: Identify Parental Generation (P)
- Pure tall plant genotype = $TT$
- Pure dwarf plant genotype = $tt$
Step 2: Determine Gametes
- The tall plant ($TT$) produces gametes carrying the allele: $T$
- The dwarf plant ($tt$) produces gametes carrying the allele: $t$
Step 3: F1 Generation Cross and Results
- Fertilization between gamete $T$ and gamete $t$ results in the F1 generation offspring with the genotype $Tt$.
- Phenotype of F1 generation: All plants are tall because the 'T' (tall) allele is completely dominant over the 't' (dwarf) allele.
- F1 Genotypic Ratio: 100% $Tt$ ( heterozygous tall )
- F1 Phenotypic Ratio: 100% Tall
Step 4: F2 Generation Cross (Selfing of F1)
- Two F1 plants ($Tt \times Tt$) are crossed.
- Gametes from each parent: $T$ and $t$.
- Using a Punnett square:
- Top row gametes: $T$ (50%), $t$ (50%)
- Left column gametes: $T$ (50%), $t$ (50%)
- Resulting offspring genotypes: $TT$ (1), $Tt$ (2), $tt$ (1).
Step 5: F2 Ratios Calculation
- Genotypic Ratio: $1 (TT) : 2 (Tt) : 1 (tt)$ or $1:2:1$
- Phenotypic Ratio: $3 \text{ Tall} : 1 \text{ Dwarf}$ or $3:1$
Conclusion & Law:\nFrom this monohybrid cross, Mendel formulated the Law of Segregation (First Law), which states that alleles of a gene separate during gamete formation so that each gamete carries only one allele for each gene.
💡 Study Guide: This question tests core syllabus concepts from Heredity and Evolution. For formulas, key summaries, and mock exam reference guides, read the full Heredity and Evolution Revision Notes.