MP Board · Class 10 · Mathematics · Real NumbersGiven that HCF(306, 657) = 9, find LCM(306, 657).
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Step-by-Step Solution
We know the standard relation for any two positive integers a and b that HCF(a, b) × LCM(a, b) = a × b. Here, let a = 306 and b = 657, and HCF(306, 657) = 9. Substituting these values into the formula, we get 9 × LCM = 306 × 657. Solving for LCM, we get LCM = (306 × 657) / 9 = 34 × 657 = 22338. Therefore, the required LCM is 22338.
💡 Study Guide: This question tests core syllabus concepts from Real Numbers. For formulas, key summaries, and mock exam reference guides, read the full Real Numbers Revision Notes.