MP Board · Class 10 · Mathematics · Real NumbersIf $n$ is any natural number, then $6^n$ always ends with the digit:
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Total Attempts: 14
Accuracy Rate: 42.9%
Step-by-Step Solution
The correct answer is A (6).
Explanation:\nFor any natural number $n$, $6^n = (2 \times 3)^n = 2^n \times 3^n$. Since it contains factors of 2 and 3, but not 5, it will never have 0 as its units digit. Calculating a few values: $6^1 = 6$, $6^2 = 36$, $6^3 = 216$. It always ends with 6.
Detailed Options Breakdown
Option : 6 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 4
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Real Numbers.
Option 2: 0
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Real Numbers.
Option 3: 5
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Real Numbers.
💡 Study Guide: This question tests core syllabus concepts from Real Numbers. For formulas, key summaries, and mock exam reference guides, read the full Real Numbers Revision Notes.