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MP Board · Class 10 · Mathematics · Pair of Linear Equations in Two VariablesA boat goes $30\text{ km}$ upstream and $44\text{ km}$ downstream in $10\text{ hours}$. In $13\text{ hours}$, it can go $40\text{ km}$ upstream and $55\text{ km}$ downstream. Formulate the pair of linear equations and find the speed of the stream and that of the boat in still water.

Step-by-Step Solution

Step-by-step Solution:

Step 1: Define variables

  • Let the speed of the boat in still water = $x\text{ km/h}$
  • Let the speed of the stream = $y\text{ km/h}$ \nThen,
  • Speed of the boat upstream = $(x - y)\text{ km/h}$
  • Speed of the boat downstream = $(x + y)\text{ km/h}$

Step 2: Formulate equations using $\text{Time} = \frac{\text{Distance}}{\text{Speed}}$

  • Case 1: Time taken for $30\text{ km}$ upstream + Time taken for $44\text{ km}$ downstream = $10\text{ hours}$ $$\frac{30}{x - y} + \frac{44}{x + y} = 10 \quad \text{--- (Equation 1)}$$

  • Case 2: Time taken for $40\text{ km}$ upstream + Time taken for $55\text{ km}$ downstream = $13\text{ hours}$ $$\frac{40}{x - y} + \frac{55}{x + y} = 13 \quad \text{--- (Equation 2)}$$


Step 3: Reduce to linear equations\nLet $\frac{1}{x - y} = u$ and $\frac{1}{x + y} = v$. \nSubstituting $u$ and $v$ into Equations 1 and 2: $$30u + 44v = 10 \quad \implies \quad 15u + 22v = 5 \quad \text{--- (Equation 3)}$$ $$40u + 55v = 13 \quad \text{--- (Equation 4)}$$


Step 4: Solve the reduced linear equations\nMultiply Equation 3 by $8$ and Equation 4 by $3$: $$120u + 176v = 40 \quad \text{--- (Equation 5)}$$ $$120u + 165v = 39 \quad \text{--- (Equation 6)}$$ \nSubtracting Equation 6 from Equation 5: $$(120u - 120u) + (176v - 165v) = 40 - 39$$ $$11v = 1 \implies v = \frac{1}{11}$$ \nSubstitute $v = \frac{1}{11}$ in Equation 3: $$15u + 22\left(\frac{1}{11}\right) = 5$$ $$15u + 2 = 5 \implies 15u = 3 \implies u = \frac{3}{15} = \frac{1}{5}$$


Step 5: Find $x$ and $y$\nSince $u = \frac{1}{x - y} = \frac{1}{5}$: $$x - y = 5 \quad \text{--- (Equation 7)}$$ \nSince $v = \frac{1}{x + y} = \frac{1}{11}$: $$x + y = 11 \quad \text{--- (Equation 8)}$$ \nAdding Equation 7 and Equation 8: $$(x - y) + (x + y) = 5 + 11$$ $$2x = 16 \implies x = 8$$ \nSubstituting $x = 8$ in Equation 8: $$8 + y = 11 \implies y = 3$$


Final Answer:

  • Speed of the boat in still water = $8\text{ km/h}$
  • Speed of the stream = $3\text{ km/h}$
💡 Study Guide: This question tests core syllabus concepts from Pair of Linear Equations in Two Variables. For formulas, key summaries, and mock exam reference guides, read the full Pair of Linear Equations in Two Variables Revision Notes.
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