MP Board · Class 10 · Mathematics · Pair of Linear Equations in Two VariablesRitu can row downstream $20\text{ km}$ in $2\text{ hours}$, and upstream $4\text{ km}$ in $2\text{ hours}$. Formulate the system of linear equations representing this situation. Find her speed of rowing in still water and the speed of the current using the elimination method. Show complete step-by-step calculations and verification.
Step-by-Step Solution
Step 1: Define variables\nLet the speed of Ritu in still water = $x\text{ km/h}$\nLet the speed of the stream (current) = $y\text{ km/h}$
Step 2: Determine relative speeds
- Speed downstream $= (x + y)\text{ km/h}$
- Speed upstream $= (x - y)\text{ km/h}$ \nWe know the formula: $$\text{Speed} = \frac{\text{Distance}}{\text{Time}} \quad \implies \quad \text{Distance} = \text{Speed} \times \text{Time}$$
Step 3: Formulate Linear Equations
Condition 1: Downstream motion
- Distance = $20\text{ km}$, Time = $2\text{ hours}$ $$(x + y) \times 2 = 20$$ $$x + y = 10 \quad \text{--- (Equation 1)}$$
Condition 2: Upstream motion
- Distance = $4\text{ km}$, Time = $2\text{ hours}$ $$(x - y) \times 2 = 4$$ $$x - y = 2 \quad \text{--- (Equation 2)}$$
Step 4: Solve the system using Elimination Method
\nAdding Equation (1) and Equation (2): $$(x + y) + (x - y) = 10 + 2$$ $$2x = 12$$ $$x = \frac{12}{2} = 6$$ \nSubstitute $x = 6$ into Equation (1): $$6 + y = 10$$ $$y = 10 - 6 = 4$$
Step 5: Verification of Results
- Downstream speed $= 6 + 4 = 10\text{ km/h}$ Time taken $= \frac{20}{10} = 2\text{ hours}$ (Matches given data)
- Upstream speed $= 6 - 4 = 2\text{ km/h}$ Time taken $= \frac{4}{2} = 2\text{ hours}$ (Matches given data)
Final Answer
- Speed of rowing in still water $= 6\text{ km/h}$
- Speed of the current $= 4\text{ km/h}$
💡 Study Guide: This question tests core syllabus concepts from Pair of Linear Equations in Two Variables. For formulas, key summaries, and mock exam reference guides, read the full Pair of Linear Equations in Two Variables Revision Notes.