CBSE · Class 12 · Physics · Moving Charges and MagnetismWhat is the magnetic field at the center of a circular current-carrying coil of radius $R$ and current $I$?
Step-by-Step Solution
According to Bio-Savart law, the magnetic field at the center of a circular coil of radius $R$ carrying current $I$ with a single turn is given by $B = \frac{\mu_0 I}{2R}$.
Detailed Options Breakdown
Option : mu_0 I / R
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Moving Charges and Magnetism.
Option 1: mu_0 I / (2R) (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: 2 mu_0 I / R
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Moving Charges and Magnetism.
Option 3: mu_0 I / (4R)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Moving Charges and Magnetism.
💡 Study Guide: This question tests core syllabus concepts from Moving Charges and Magnetism. For formulas, key summaries, and mock exam reference guides, read the full Moving Charges and Magnetism Revision Notes.