CBSE · Class 12 · Physics · Electrostatic Potential and CapacitanceThe relation between electric field $E$ and potential gradient is:
Step-by-Step Solution
Electric field is negative gradient of electric potential, $E = -\frac{dV}{dr}$.
Detailed Options Breakdown
Option : $E = \frac{dV}{dr}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrostatic Potential and Capacitance.
Option 1: $E = -\frac{dV}{dr}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $V = -\frac{dE}{dr}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrostatic Potential and Capacitance.
Option 3: $E = -V \cdot dr$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electrostatic Potential and Capacitance.
💡 Study Guide: This question tests core syllabus concepts from Electrostatic Potential and Capacitance. For formulas, key summaries, and mock exam reference guides, read the full Electrostatic Potential and Capacitance Revision Notes.