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CBSE · Class 12 · Physics · Alternating CurrentWhat is electrical resonance in a series LCR circuit? Derive the expression for the resonant frequency of a series LCR circuit.

Step-by-Step Solution

Electrical Resonance in Series LCR Circuit:\nElectrical resonance is a phenomenon in a series LCR circuit in which, at a particular frequency of the applied alternating voltage, the inductive reactance ($X_L$) becomes equal to the capacitive reactance ($X_C$). At this specific frequency, the total impedance of the circuit becomes minimum and equal to the resistance ($Z = R$), resulting in a maximum flow of alternating current through the circuit.

Derivation of Resonant Frequency ($f_r$):\nThe impedance of a series LCR circuit is given by: $$Z = \sqrt{R^2 + (X_L - X_C)^2}$$ \nAt resonance, $X_L = X_C$. \nSince $X_L = \omega_r L$ and $X_C = \frac{1}{\omega_r C}$: $$\omega_r L = \frac{1}{\omega_r C}$$ $$\omega_r^2 = \frac{1}{LC}$$ $$\omega_r = \frac{1}{\sqrt{LC}}$$ \nSince angular frequency $\omega_r = 2\pi f_r$, where $f_r$ is the resonant frequency: $$2\pi f_r = \frac{1}{\sqrt{LC}}$$ $$f_r = \frac{1}{2\pi\sqrt{LC}}$$ \nThis expression gives the resonant frequency of a series LCR circuit.

💡 Study Guide: This question tests core syllabus concepts from Alternating Current. For formulas, key summaries, and mock exam reference guides, read the full Alternating Current Revision Notes.
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