CBSE · Class 12 · Chemistry · ElectrochemistryWhat are primary and secondary batteries? Explain the structure, operation, and chemical reactions of Leclanché cell (dry cell) and lead-storage battery with suitable equations.
Step-by-Step Solution
Introduction to Batteries
Batteries are essentially galvanic cells where chemical energy of redox reactions is converted into electrical energy. They are mainly classified into two categories:
- Primary Batteries: In these batteries, the reaction occurs only once, and after some time of use, the battery dies, and it cannot be recharged or reused. Example: dry cell, mercury cell.
- Secondary Batteries: These batteries can be recharged by passing current in the opposite direction so that they can be used repeatedly. Example: lead-storage battery, nickel-cadmium cell.
1. Leclanché Cell (Dry Cell)
- Structure: A standard dry cell consists of a zinc cylinder acting as the anode. The cylinder is filled with a moist paste of ammonium chloride ($NH_4Cl$) and zinc chloride ($ZnCl_2$). Inside the paste, a carbon (graphite) rod is placed, acting as the cathode. Around the carbon rod, a mixture of manganese dioxide ($MnO_2$) and powdered carbon is present.
- Operation and Reactions:
- Anode (Oxidation): Zinc is oxidized to form zinc ions. $$Zn(s) ightarrow Zn^{2+} + 2e^{-}$$
- Cathode (Reduction): Manganese dioxide undergoes reduction, where the oxidation state of $Mn$ changes from +4 to +3, and $NH_4^+$ ions are consumed. $$MnO_2 + NH_4^+ + e^{-} ightarrow MnO(OH) + NH_3$$
- Complex Formation: The ammonia ($NH_3$) formed in the reaction combines with $Zn^{2+}$ ions to form $[Zn(NH_3)_4]^{2+}$ complex ions, maintaining the cell potential.
- Potential: The potential of this cell is approximately $1.5 V$.
2. Lead-Storage Battery
- Structure: This is the most important secondary cell widely used in automobiles and inverters. It consists of a lead anode and a grid cathode made of lead dioxide ($PbO_2$). Sulfuric acid ($H_2SO_4$) at 38% concentration is used as the electrolyte.
- Discharge (Discharging) Operation and Reactions:
- Anode Reaction: Lead sulfate ions react with lead to form lead sulfate. $$Pb(s) + SO_4^{2-}(aq) ightarrow PbSO_4(s) + 2e^{-}$$
- Cathode Reaction: Lead dioxide undergoes reduction in the presence of sulfuric acid and protons to form lead sulfate. $$PbO_2(s) + SO_4^{2-}(aq) + 4H^+(aq) + 2e^{-} ightarrow PbSO_4(s) + 2H_2O(l)$$
- Overall Cell Reaction: $$Pb(s) + PbO_2(s) + 2H_2SO_4(aq) ightarrow 2PbSO_4(s) + 2H_2O(l)$$
- Charging: When the battery is charged, the cell reactions occur in the opposite direction, and lead sulfate is converted back to lead and lead dioxide.
💡 Study Guide: This question tests core syllabus concepts from Electrochemistry. For formulas, key summaries, and mock exam reference guides, read the full Electrochemistry Revision Notes.