CBSE · Class 11 · Physics · WavesWhat is the ratio of fundamental frequencies of a closed organ pipe and an open organ pipe of the same length?
Step-by-Step Solution
Correct Option: $1 : 2$ \nFundamental frequency of closed pipe $f_c = \frac{v}{4L}$ and open pipe $f_o = \frac{v}{2L}$.\nRatio $\frac{f_c}{f_o} = \frac{v/4L}{v/2L} = \frac{1}{2}$, i.e., $1:2$.
Detailed Options Breakdown
Option : 1 : 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Waves.
Option 1: 1 : 2 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: 2 : 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Waves.
Option 3: 1 : 4
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Waves.
💡 Study Guide: This question tests core syllabus concepts from Waves. For formulas, key summaries, and mock exam reference guides, read the full Waves Revision Notes.