CBSE · Class 11 · Physics · System of Particles and Rotational MotionTwo particles of masses $1\text{ kg}$ and $3\text{ kg}$ are located at positions $(0,0)$ and $(4,0)\text{ m}$ respectively. The $x$-coordinate of their center of mass is:
Step-by-Step Solution
The $x$-coordinate of center of mass is $X_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} = \frac{1(0) + 3(4)}{1 + 3} = \frac{12}{4} = 3\text{ m}$.
Detailed Options Breakdown
Option : $1\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 1: $2\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 2: $3\text{ m}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: $4\text{ m}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
💡 Study Guide: This question tests core syllabus concepts from System of Particles and Rotational Motion. For formulas, key summaries, and mock exam reference guides, read the full System of Particles and Rotational Motion Revision Notes.