CBSE · Class 11 · Physics · System of Particles and Rotational MotionThe moment of inertia of a solid sphere of mass $M$ and radius $R$ about its diameter is:
Step-by-Step Solution
For a uniform solid sphere, the moment of inertia about any axis passing through its center (diameter) is $I = \frac{2}{5}MR^2$.
Detailed Options Breakdown
Option : $\frac{2}{3}MR^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 1: $\frac{2}{5}MR^2$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $\frac{1}{2}MR^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
Option 3: $\frac{7}{5}MR^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of System of Particles and Rotational Motion.
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