CBSE · Class 11 · Physics · OscillationsIf a spring of spring constant $k$ is cut into two equal halves, the spring constant of each half will be:
Step-by-Step Solution
The spring constant $k$ is inversely proportional to length $l$ ($k \propto 1/l$). When length is halved ($l' = l/2$), the spring constant doubles ($k' = 2k$).
Detailed Options Breakdown
Option : $k/2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 1: $k$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 2: $2k$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: $4k$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.