CBSE · Class 11 · Physics · OscillationsThe maximum acceleration of a particle executing SHM with amplitude $A$ and angular frequency $\omega$ is:
Step-by-Step Solution
Acceleration in SHM is $a = -\omega^2 x$. Maximum magnitude of acceleration occurs at the extreme positions ($x = \pm A$), which gives $a_{\max} = \omega^2 A$.
Detailed Options Breakdown
Option : $A\omega$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 1: $\omega^2 A$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $\omega A^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 3: $A/\omega^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.