CBSE · Class 11 · Physics · Mechanical Properties of SolidsIf a wire of original length $L$ and area $A$ elongates by $\Delta L$ under a force $F$, what is the expression for Young's modulus $Y$?
Step-by-Step Solution
Young's modulus $Y = \frac{\text{Longitudinal Stress}}{\text{Longitudinal Strain}} = \frac{F/A}{\Delta L / L} = \frac{F \cdot L}{A \cdot \Delta L}$.
Detailed Options Breakdown
Option : $Y = \frac{F \cdot L}{A \cdot \Delta L}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $Y = \frac{F \cdot \Delta L}{A \cdot L}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Solids.
Option 2: $Y = \frac{A \cdot L}{F \cdot \Delta L}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Solids.
Option 3: $Y = \frac{F \cdot A}{L \cdot \Delta L}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Mechanical Properties of Solids.
💡 Study Guide: This question tests core syllabus concepts from Mechanical Properties of Solids. For formulas, key summaries, and mock exam reference guides, read the full Mechanical Properties of Solids Revision Notes.